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    zqueez's Avatar
    zqueez Posts: 33, Reputation: 1
    Junior Member
    		  
    #1

    Nov 12, 2008, 07:15 AM
    Finding Driving Speeds
    A girl drove 300 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.

    I just want to know how to set up this problem. The fact that her return took 1 hour less time is throwing me off.

    Can someone help me?

    Thank you.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Nov 12, 2008, 08:21 AM

    Using the basic equation that distance = velocity times time:

    D = VT

    On the way out she drove 300 miles at V MPH, and on the return she drove at V + 11 MPH. The time driving out is T, and the time driving back is T-1. So you have 2 equations in 2 unknowns:

    300= VT
    300 = (V+11)(T-1)

    Can you take it from here?
    zqueez's Avatar
    zqueez Posts: 33, Reputation: 1
    Junior Member
    		  
    #3

    Nov 12, 2008, 08:43 AM
    Thank you so much!
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