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    Eelarch's Avatar
    Eelarch Posts: 116, Reputation: 3
    Junior Member
     
    #1

    May 3, 2010, 04:12 AM
    Finding a and b in un+1 = aun + b
    In advance sorry for the very collumn layout but I tihnk it makes the question a lot clearer.

    un+1 = aun + b

    u1 = 5,
    u2 = 9.5,
    u3 = 20.75

    so

    9.5= a(5) +b
    20.75= a(9.5) + b

    now I am not sure what to do from here one, should you combine both the equations or do a simultanious equation?

    Combining

    30.25 = 2a(47.5) +2b

    x/2

    15.125 = a(47.5) + b

    15.125 - b = a(47.5)

    (15.125 -b)/47.5 = a

    I'm not sure if this is the right route since I have a and b on either sidebut I'm lost from here, any help would be appreciated:)
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    May 3, 2010, 06:36 AM

    You actually need to solve them simultaneously.

    I don't see any point in combining them this way, though that can work for some equations. The general way we call is solving simultaneously by elimination. If you want to 'combine' the equations, you'll be better off subtracting one from the other.

    Can you try it now and post what you get? :)
    Eelarch's Avatar
    Eelarch Posts: 116, Reputation: 3
    Junior Member
     
    #3

    May 5, 2010, 09:54 AM

    9.5= a(5) +b
    20.75= a(9.5) + b

    11.25=a(4.5)+ b

    is the rest guess work because I still have two variables on a side
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
     
    #4

    May 5, 2010, 09:59 AM

    Come on!

    Code:
    20.75 = 9.5a + 1b  -
     9.50 = 5.0a + 1b
    11.25 = 4.5a + 0b
    :)
    Eelarch's Avatar
    Eelarch Posts: 116, Reputation: 3
    Junior Member
     
    #5

    May 5, 2010, 12:38 PM

    ah thank you so much =] what's probably quite scary is that I got an A yesterday in a practice paper, its these silly things like this that trip me on my face. Thanks
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
     
    #6

    May 6, 2010, 12:30 AM

    No worries, that sometimes happens, better double check for those kinds of mistakes. These ones are quite easy to spot because you have one b in each equation and by elimination, it is only natural that none should remain. If you are more familiar with other methods such as substitution, use them as a check.

    Good luck! :)

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