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    lorenzo822's Avatar
    lorenzo822 Posts: 1, Reputation: 1
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    #1

    Oct 5, 2011, 10:50 AM
    Find the ordered triple of these equations.
    x + 2y + 2z = 0 2x + y + z = 3 x - 3y - z = 1
    FadedMaster's Avatar
    FadedMaster Posts: 1,510, Reputation: 148
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    #2

    Oct 5, 2011, 06:18 PM
    Please note that we do not give answers on here, but we do help you with your homework. Have you made any attempts on your problem? If so, please post them. If not, please let us know where you are stuck.

    Also, please try using some of the math code, your equations are difficult to understand.

    https://www.askmehelpdesk.com/math-s...las-50415.html
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #3

    Oct 6, 2011, 03:22 AM
    x + 2y + 2z = 0
    2x + y + z = 3
    x - 3y - z = 1

    Take 1st and 2nd equations and solve simultaneously to elimintate y and z at the same time and get x.

    Then use that value of x in all the equations to get them in terms of y and z only, where you can use simultaneous equations to solve for the remaining variables.
    FadedMaster's Avatar
    FadedMaster Posts: 1,510, Reputation: 148
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    #4

    Oct 6, 2011, 05:29 AM
    Quote Originally Posted by Unknown008 View Post
    x + 2y + 2z = 0
    2x + y + z = 3
    x - 3y - z = 1

    Take 1st and 2nd equations and solve simultaneously to elimintate y and z at the same time and get x.

    Then use that value of x in all the equations to get them in terms of y and z only, where you can use simultaneous equations to solve for the remaining variables.
    Thanks for rewriting that (I have to spread rep otherwise I would give you a greenie) I was too tired after 8.5 hours straight of work followed by a 3 hour chemistry exam. Haha.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #5

    Oct 6, 2011, 05:30 AM
    It's okay, I was confused too at first and seeing that the equation was abnormally long... noticed the spaces ;)
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