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    Jaybird11's Avatar
    Jaybird11 Posts: 1, Reputation: 1
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    #1

    Feb 21, 2011, 08:03 PM
    Find all the real zeros f(x)=-2x^4+4x^3-2x^2
    jcaron2's Avatar
    jcaron2 Posts: 986, Reputation: 204
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    #2

    Feb 21, 2011, 08:46 PM

    Notice that you can factor an x^2 out of all the terms. Once you do that, it simply leaves a quadratic, which you can solve with the quadratic equation. Once it's factored, do you know how to find the zeros?
    Mr_period_C's Avatar
    Mr_period_C Posts: 2, Reputation: 1
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    #3

    Feb 22, 2011, 05:20 PM
    Comment on jcaron2's post
    I would factor out -2x^2, leaving you with x^2 -2x + 1, which factors to (x-1)^2
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