Check out some similar questions!

klang31 · Jun 29, 2009, 06:50 AM

How many grams of C are in 4.20x10 to the power of 23 molecules of (C3H5)2S?

I am not sure what the formula is that I am supposed to use to figure this out.

Perito · Jun 29, 2009, 07:15 AM

Avogadro's number = $6.0221415 \times 10^{23}$

One mole of any material contains Avogadro's number of molecules.

Let's show you with an example. The atomic weight of oxygen is approximately 16. The molecular formula for oxygen is $O_2$ . Since there are two atoms of oxygen in a molecule, the molecular weight of $O_2$ is 32. Therefore, in 32 grams of oxygen, there are $6.0221415 \times 10^{23}$ molecules of oxygen.

You have $4.20 \times 10^{23}$ molecules of $(C_3H_5)_2S$ .

1. Calculate the number of moles of that substance.

2. Calculate the molecular weight of that substance

3. Multiply moles by molecular weight (grams per mole)

$Grams = moles \,\times\, \frac {grams}{mole}$