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    VICTOR101010101's Avatar
    VICTOR101010101 Posts: 1, Reputation: 1
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    #1

    Jun 18, 2012, 08:17 AM
    Calculus
    solve for x, e^x+1=0
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Jun 18, 2012, 08:28 AM
    Quote Originally Posted by VICTOR101010101 View Post
    solve for x, e^x+1=0
    Have you studied d'Moivre's theorem?



    where is a real number. Here you need to find a value for such that and .
    cyber_i9's Avatar
    cyber_i9 Posts: 9, Reputation: 1
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    #3

    Jun 19, 2012, 07:59 AM
    well, I guess we can Manipulate the equation,
    given: e^x+1=o
    :- e^x= -1
    :- taking log on both sides
    :- x = -log 1 ( log and e cancel out)
    therefore,
    :- x = 0
    hope it works, bcoz its just a Hunch!
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Jun 19, 2012, 09:09 AM
    Quote Originally Posted by cyber_i9 View Post
    well, i guess we can Manipulate the equation,
    given: e^x+1=o
    :- e^x= -1
    You made a mistake there. From e^x+1=0 you get e^x = -1, which leads to x = ln(-1). Hence the need to apply complex numbers.

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