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    mathletic Posts: 5, Reputation: 1
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    May 21, 2014, 05:54 AM
    Calculating the coefficients
    I am solving an initial-boundary value problem and I got to a point that I have to calculate the coefficients knowing that:
    x=Σ{An sin(((2n+1) π x)/(2L))}


    One way to calculate the coefficient is the Fourier series, isn't it?


    So I thought the following:


    We expand the function f(x)=x in an odd way at [-L,L].


    So we can write the function as a Fourier series.


    Can we write it as followed?


    f(x)=Σ{bn sin((2(2n+1) π x)/(2 * 2L))},
    where bn= 2/(4L) ∫_{-L}^L{f(x) sin((2 (2n+1) π x)/(4L))}dx


    Or can we not do this in this way?

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