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ajone216 · Dec 15, 2009, 12:01 PM

f'(x)= x^2√2x^3+1

what's f(x)

I get the concept and did well on my test, but I just can't seem to figure out how to get the answer.

the answer is 1/9(2x^3=1)^3/2+C

ebaines · Dec 15, 2009, 12:20 PM

Pleasw, please, use parentheses to make the equations clearer! I'm guessing that what you mean is:

$<br /> f'(x) = x^2 \sqrt { 2x^3+1}<br />$

and
$<br /> f(x) = \frac 1 9 (2x^3 +1)^{3/2} + C<br />$

Is that correct?

First steps first - do you see that the derivative of f(x) is indeed equal to f'(x) as written?