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MelRoxMySox12 · Aug 27, 2007, 02:43 PM

how do you solve this problem:

Factor Completely:
2x(squared)-3x-5

galactus · Aug 27, 2007, 03:12 PM

$2x^{2}-3x-5$

What two numbers when added equal -3 and when multiplied equal -10?

$a+b=-3, \;\ ab=-10$

Then use those to factor.

$2x^{2}+ax+bx-5$

Group:

$(2x^{2}+ax)+(bx-5)$

Factor out a common factor and make sure what is inside the parentheses is the same, otherwise, it won't work correctly.

Let me know what you get for your two numbers.