wateverlala Posts: 2, Reputation: 1 New Member #1 Oct 25, 2007, 05:01 PM
algebra 1
find the greatest possible pair of integers that one integer is twice the other and their sum is less than 30.
 Gernald Posts: 901, Reputation: 93 Expert #2 Oct 25, 2007, 06:05 PM
Less then thirty or 30 exactly?
Start with numbers that can be halved that eliminates most. Then start adding them up and try to get 30 or below thirty.
like 2 and 4 then 2+4=6 that makes it but its not the greatest it can be.
try higher numbers like 20 and 10 20+10 makes exactly thirty but its not right because it has to be less then thirty.
So since 19 won't work try 18 and its half 9. 18+9=27
I'm sure there's an easier way to do it, but I always like to think it out logically because I can't stand math.
 eawoodall Posts: 230, Reputation: 5 Full Member #3 Oct 27, 2007, 12:16 AM
a +b <30.
b=2a.
a +2a <30.
3a <30.
a <10.
what is the biggest integer less than ten?
nine.
a=9.
b = 2a = 2(9) =18.
b =18.
9 +18 <30.
27 <30.
true.

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