I've been spending the last 3 or so hours on this problem and I cannot figure it out! 5x^3=5x^2+12x I subtract the 5x^3 to get it on one side so that it equals to zero. Now when I take out the GCF of x it leaves me with x(-5x^2+5x+12) and from there I have no idea... You can't multiply 12 and...

consider the function f(x)= x^3+6x^2+9x+4 -state the intervals over which f(x)>0 and f(x)<0 && - show that there is a local maximum at x=3 and state the coordinate.

I'm doing some math homework, but I have one polynomial inequality that isn't divisble by one or anything else so I can't factor it. What am I supposed to do?

Using transformations and the zeros of the polynomial function f(x)=x(x-4)(x+2) how could you determine the zeros of y=f(2x)?? Thanks

How would you solve x^3-3x^2+2=0? Given P(x)=x^3-2x^2-x+8 how could you use its graph to solve x^3-2x^2>4x-8? Does it show you where it shifts and to what quadrant? I'm confused. What is the solution to x^3-2x^2>4x-8? Thank you.