|1-a^2| / 5a > 3

endlesslove230 · Nov 20, 2011, 06:11 AM

$\frac{|1-a^2|}{5a}>3, && a\epsilon R$

How do I calculate the value of a from this expression?

Aurora2000 · Nov 20, 2011, 08:06 AM

It is an inequality, not an equation, what you have as solution is something like "a greater than... / a in... ".

First look at signs: what happens if a<0?
Absolute values are always non negative: if $1-a^2<0$ then $|1-a^2|=-(1-a^2)$ , if $1-a^2\geq 0$ then $|1-a^2|=1-a^2$ . Solve these 2 cases separately (they are II degree equation), and do not forget the constrains on a put when you split the absolute value in these 2 cases.