xsw21232 Posts: 1, Reputation: 1 New Member #1 Mar 12, 2015, 06:06 AM
I need help in solving permutation sum
In how many ways can a person can courier/parcel to his 5 friends if he has four courier options.
 ebaines Posts: 12,132, Reputation: 1307 Expert #2 Mar 12, 2015, 01:10 PM
For friend A there are four possible ways to send a parcel, call then A1, A2, A3, and A4. For friend B there are also four ways - B1, B2, B3,and B4 - so between both friends A and B there are 4x4 = 16 different possible combinations. It can help to write these out so that see how it works:

A1&B1, A1&B2, A1&B3, A1&B4
A2&B1, A2&B2, A2&B3, A2&B4
A3&B1, A3&B2, A3&B3, A3&B4
A4&B1, A1&B2, A4&B3, A4&B4

So now how would this extend to include a third friend? And how about a fourth, and finally a fifth friend?
 fgsfgsfd Posts: 1, Reputation: 1 New Member #3 Mar 12, 2015, 11:57 PM
Could you differentiate the two sums below
1.In how many ways can a person can courier/parcel to his 5 friends if he has four courier options.
2. In how many ways can 4 gifts be distributed to 6 children if each child get any number of gifts

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