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    ashliss07's Avatar
    ashliss07 Posts: 1, Reputation: 1
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    #1

    May 9, 2007, 12:25 PM
    Solving using elimination.
    Doe anyone know some of these answers? Please help!! :confused:

    x + y = 10
    x - y = 4



    4x - 3y = -2
    -2x + 3y = 4


    3x - 4y = -2
    4x - 3y = -5



    x + 4y = -5
    3x + y = -4


    2x - y = 10
    x + 2y = -5
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    May 9, 2007, 12:48 PM
    Ashliss07:

    We won't do your homework for you, but here is a hint:

    Each problem you've listed is a pair of statements with two unkowns (x and y). Take one of the statements and rephrase it so that either the x or the y is by itself on one side of the equation. You can then substitute that value into the other statement to determine one of the values. For example: the first problem includes the equation: x-y = 4. You can add y to both sides of the equal sign to get: x = 4+y. Do you see that? Then substitute this value for x into the first equation, so that x+y = 10 becomes (4+y) + y = 10. Now you can solve for y. Get it?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #3

    May 9, 2007, 01:02 PM
    ebainesm the topic says to solve using elimination, not substitution.

    Ashliss07, if you look at your first pair of equations, you see that you have +y in one and -y in the other. If you add the equations together, you get 2x = 14 because the y terms disappear, this gives you a value for x, which you can use to solve for y.

    In the later questions, you might have to multiply up one of your equations in order to get a term that will disappear.

    Please ask if you need further help.
    deez5112's Avatar
    deez5112 Posts: 2, Reputation: 1
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    #4

    Jun 26, 2010, 01:57 PM
    x+y=8,000
    x+y=600
    deez5112's Avatar
    deez5112 Posts: 2, Reputation: 1
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    #5

    Jun 26, 2010, 01:57 PM

    x+y=8,000
    x+y=600
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #6

    Jun 27, 2010, 05:08 AM

    The problem you posted here, deez5112 doesn't have any solutions. If, however, you meant:

    x + y = 8 000
    x - y = 600

    Then, that's something different. Add the two equations:

    Code:
     x + y = 8000
     x - y =  600
    2x + 0 = 8600
    Now that you have only one variable, you can solve the rest. :)

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