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    larry567's Avatar
    larry567 Posts: 1, Reputation: 1
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    #1

    Apr 9, 2012, 01:15 PM
    Prove Trig identity
    sin(x+y)cos(x-y) = (sinx/secx) + (cosyy/cscy)

    prove that both sides equal each other
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Apr 10, 2012, 06:27 AM
    On the left hand side you can apply the identities sin(x+y) = sin(x)cos(y)+cos(x)sin(y) and cos(x-y) = cos(x)cos(y)+sin(x)sin(y). On the right hand side replace the sec(x) and csc(y) terms by their sine and cosine equivalents. It comes right out after some algebra manipulation (and remember that cos^2a + sin^2a = 1).
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