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    theguywithnolife's Avatar
    theguywithnolife Posts: 82, Reputation: 10
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    #1

    Feb 17, 2009, 03:10 PM
    Polynomial Equations
    I've been spending the last 3 or so hours on this problem and I cannot figure it out!

    5x^3=5x^2+12x

    I subtract the 5x^3 to get it on one side so that it equals to zero. Now when I take out the GCF of x it leaves me with x(-5x^2+5x+12) and from there I have no idea... You can't multiply 12 and negative 5 and find somethat when when multipied =-60 but when added get 5. When I do the quadratic Formula I end up getting something like 2i square root 43 and I'm not sure that sounds right since I need 3 answers seeing as how the highest exponet is 3
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Feb 18, 2009, 11:13 AM

    You are on the right track. So far you have:

    0 = x(-5x^2 + 5x +12)

    From this you already have one of your solutions - namely x=0. To get the other two solutions apply the quadratic formula (since you can't just factor -5x^2 + 5x +12). You will end up with two more solutions, but be careful of signs - you should find the solutions involve the square root of a positive number, not negative.
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