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    Jason Townsend's Avatar
    Jason Townsend Posts: 1, Reputation: 1
    New Member

    Dec 11, 2006, 11:41 AM
    Invisible dog fence electric use
    Hi, our invisble dog fence is rated "12V, 850mA" How do I figure out how much electricity this fence is using/unit time when it's on? Thanks much.
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
    Uber Member

    Dec 11, 2006, 12:01 PM
    P = IV

    = 12*0.85 W

    it uses 12*0.85 Watt-hours per hour.
    tkrussell's Avatar
    tkrussell Posts: 9,659, Reputation: 725
    Uber Member

    Dec 11, 2006, 03:36 PM
    I think Capuchin lost track a bit, and gave a wrong answer by mistake.

    Power= Volts times amps
    P= 12 volts x .85 amps
    P=10.2 watts

    To calculate cost per month:
    KiloWattHour=10.2 watts times 1 hour =.0102 KWH per hour of operation
    .0102 KWH times 720 hours (30 day)=7.344 Total KWH per month
    7.344 KWH at .10 cents per KWH= .74 cents per month cost to operate.

    Insert your KWH cost in the place of ten cents to arrive at your true cost, we pay dearly for electricity here in the northeast.
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
    Uber Member

    Dec 12, 2006, 12:47 AM
    I have no idea how electricity is measured, that's my problem ;)
    But I think I was correct apart from that.

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