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    xox-kay77kay-xox's Avatar
    xox-kay77kay-xox Posts: 1, Reputation: 1
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    #1

    Oct 10, 2007, 03:37 PM
    Oh My Goodness:Solve The System
    Solve The System

    x + √3 y = 4√2

    √3x+y=2√6


    Help! I just can't seem to figure this out. And I have no idea where to begin with it.:eek:
    terryg752's Avatar
    terryg752 Posts: 197, Reputation: 4
    Junior Member
    		  
    #2

    Oct 10, 2007, 03:43 PM
    Quote Originally Posted by xox-kay77kay-xox
    Solve The Sytem

    x + √3 y = 4√2

    √3x+y=2√6


    Help! I just can't seem to figure this out. and I have no idea where to begin with it.:eek:

    See my answer
    terryg752's Avatar
    terryg752 Posts: 197, Reputation: 4
    Junior Member
    		  
    #3

    Oct 10, 2007, 03:47 PM
    Quote Originally Posted by xox-kay77kay-xox
    Solve The Sytem

    x + √3 y = 4√2

    √3x+y=2√6


    Help! I just can't seem to figure this out. and I have no idea where to begin with it.:eek:
    Multiply first equation by square root of 3

    Then subtract the second equation, getting value of y

    Substitute value of y in second equation, getting value of x
    Ratna's Avatar
    Ratna Posts: 15, Reputation: 1
    New Member
    		  
    #4

    Oct 18, 2007, 01:15 AM
    Quote Originally Posted by xox-kay77kay-xox
    Solve The Sytem

    x + √3 y = 4√2

    √3x+y=2√6


    Help! I just can't seem to figure this out. and I have no idea where to begin with it.:eek:
    I think what u can do to remove those square roots is to multiply the whole equation with the square root. So the equation would be : x2 + 3y2 = 32(16x2) -----(1)


    3x2 + y2 = 24 (4x6)------(2)

    and then u can multiply the first equation with 3... and then minus the equation 1 and 2... so that will just leave u with y.. and there u can solve your equation.. good luck... just send me a message or quote this if u need to noe more..
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