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    shrek's Avatar
    shrek Posts: 1, Reputation: 1
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    #1

    Jun 23, 2007, 02:29 PM
    Standard enthalpy of combustion
    Here's the problem

    The heat of combustion for 1 mole of carbon to carbon dioxide is -410 kj. How many kj's of heat would be liberated from the complete combustion of 60.0 g of carbon?
    tickle's Avatar
    tickle Posts: 23,796, Reputation: 2674
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    #2

    Jun 23, 2007, 04:06 PM
    Are you talking about nuclear energy ?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #3

    Jun 23, 2007, 04:13 PM
    No tickle, this is standard molecular chemistry.

    Shrek, do you know how to calculate the mass of a single mole?
    crazygirl13455's Avatar
    crazygirl13455 Posts: 20, Reputation: 1
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    #4

    Jun 23, 2007, 08:14 PM
    If heat of comubustion and heat of fusion are the same thing then it should be 24600kJ
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    crazygirl13455 Posts: 20, Reputation: 1
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    #5

    Jun 24, 2007, 07:50 PM
    OK. Work: if it is the heat of fusion that means that the q (or heat)= mHf (mass x heat of fusion) so -410x60 = -24600 [i forgot the negative in my first answer] the negative I'm pretty sure means it's exothermic
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #6

    Jun 24, 2007, 11:30 PM
    No, you need to convert the mass into moles.
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