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    ankara55t's Avatar
    ankara55t Posts: 53, Reputation: 2
    Junior Member
     
    #1

    Dec 8, 2009, 06:20 AM
    Milliliters of 6.0MHCl
    For K2CO3 + 2HCl ---yields ---2KCl + H2O + CO2,
    How can I find the # of ml of 6.0MHCl that would be needed?
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
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    #2

    Dec 8, 2009, 06:35 AM

    Your equation appears to be balanced. Therefore, you know that for 1 mole of K2CO3, you need 2 moles of HCl.

    If you know the weight, or concentration of K2CO3, you can calculate the number of moles of K2CO3 that are present. Since you know that 1 mole of K2CO3 requires 2 moles of HCl, you can immediately calculate the number of moles of HCl that are required.

    You already gave the concentration of HCl (6 moles/liter). Therefore, for every liter you deliver, you deliver 6 moles.

    InfoJunkie4Life's Avatar
    InfoJunkie4Life Posts: 1,409, Reputation: 81
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    #3

    Dec 9, 2009, 11:05 AM

    A mole of a molecule equals the atomic weight of every atom in it added together. That number in grams is 1 mole. Don't forget, if a molecule has 2 of the same atoms in it, that atom's atomic number is counted twice, and 3: thrice, etc...

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