The calorimeter is prepared with 44.96 g of water, both at 22.6 Celsius. 2.42 g of salt are

dissolved in the water ( note the total solution mass) and the temperature falls to 19.9

Celsius . Calculate the heat of the solution for the salt. If the salt is potassium chloride,

calculate the molar heat of solution.

1. Finding the heat of solution for the salt:

water:

m = 44.96 g

T initial= 22.6 Celsius

T final= 19.9 Celsius

Salt:

m= 2.42 g

T initial= 22.6

T final= 19.9 Celsius

delta T = 2.7 Celsius

C = 4.184 J/ g Celsius

delta Q = mC delta T

= (44.96 g) ( 4.184 J/g celcius) ( 2.7 celcius)

= 507. 90 J

2. Finding the molar heat of the solution: ( really not sure about this)

m = 44.96 g

MW = 74.55 g/mol

mol = m/MW

= 44.96 g / 74.55 g/mol

= 0.603 mol

Molar heat: heat/mol

507. 90 J /0.603 mol

= 842.3 J/mol

=842.3 x 10 -3 KJ/mol