yhew Posts: 1, Reputation: 1 New Member #1 Apr 21, 2009, 08:22 AM
General Chemistry equilibrium
An acid-base equilibrium system is created by dissolving 0.10 mol HF in water to a volume of 1.0 L. What is the effect of adding 0.050mol F(aq) to this solution?
 Perito Posts: 3,139, Reputation: 150 Ultra Member #2 Apr 21, 2009, 08:55 AM

The equation for the equilibrium is

$HF\,\rightleftharpoons\,H^+\,+\,F^-$

You know the concentration of HF. You haven't given me any Ka for HF so you can't solve this quantitatively.

Remember that

$K_a=\,\frac{[H^+][F^-]}{[HF]}$

So, from that you can calculate the concentration of [F-] and figure out what happens to the equilibrium (it will drive it to the left).

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