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    varon119's Avatar
    varon119 Posts: 5, Reputation: 1
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    #1

    Nov 11, 2010, 10:16 PM
    Formation of ester
    How do you form 2-propyl cyclopentylmethanoate and 2-butyl hexanoate? Which alcohol and acid is require to produce the ester? Thanks. Your input is appreciated.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Nov 11, 2010, 10:34 PM

    2-propyl cyclopentylmethanoate

    This is formed from the acid methanoic acid because you have 'methanoate'

    Then, you have 2-propyl-cyclopentyl as the derivative of the alcohol. What do you think is the alcohol?
    DrBob1's Avatar
    DrBob1 Posts: 425, Reputation: 86
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    #3

    Nov 12, 2010, 08:05 AM
    Long ago it was noticed that an ACID + a BASE made a SALT + water and that an ACID + an ALCOHOL made an ESTER + water. These can be written as, for instance, sodium hydroxide (NaOH) + acetic acid --> sodium acetate (CH3CO2Na) + H2O and Ethyl alcohol (C2H5OH) + acetic acid --> ethyl acetate (CH3CO2C2H5)+ H2O. The ester got named like the salt. It stuck.
    So here you have esters of 2-propylcyclopentanol and methanoic acid (formic acid) and another made from 2-butanol and hexanoic acid (caproic acid). [Check the spacing in the name of your first ester -- it's incorrect]
    I'll bet they smell GOOD!

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