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    mellyiote27's Avatar
    mellyiote27 Posts: 2, Reputation: 1
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    #1

    Dec 16, 2010, 05:00 PM
    Can anyone help with this chemistry problem? Balancing with enthalpy changes?
    The molar enthalpy of formation of pyridine(liquid), C4H5N, is +100.2KJ/mol.
    a) Write the balanced equation for the formation of pyridine from its elements, that is, for the reaction for which the enthalpy of reaction is +100.2KJ.
    b) Write the balanced equation for which the enthalpy change is +200.4KJ.
    calitato's Avatar
    calitato Posts: 2, Reputation: 1
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    #2

    Dec 18, 2010, 04:44 PM
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    DrBob1's Avatar
    DrBob1 Posts: 425, Reputation: 86
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    #3

    Dec 19, 2010, 12:29 PM
    Isn't the heat of formation of pyridine NEGATIVE? Isn't the heat of formation of pyridine a constant, regardless of synthetic route? Why is the heat of formation in your second option exactly twice the first one? Now I remember why I never liked Thermo.
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    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Dec 22, 2010, 01:00 PM

    The second question asks for the 'enthalpy change' not the standard enthalpy of formation :)

    But yes, I'd expect that the enthalpy should be negative too... but according to wikipedia, the yield of this reaction is very low, so maybe it's really positive :(

    Anyway, back to the question. Could you define the term enthalpy change of formation? The answer to your first question lies in this definition.
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