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    chemdiaster's Avatar
    chemdiaster Posts: 8, Reputation: 1
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    #1

    Mar 28, 2008, 01:14 PM
    Alpha particle acceleration
    So if you have an alpha particle accelerated to 23.1 MeV per particle. How do you convert it to find the energy in kJ/mole?
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    Capuchin Posts: 5,255, Reputation: 656
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    #2

    Mar 28, 2008, 01:30 PM
    Well, you know how many J are in an eV (same as the electronic charge), and you know how many particles in a mole (Avagadro's constant), so I fail to see where you are having difficulty.
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    #3

    Mar 28, 2008, 01:41 PM
    Do you have to do anything with the alpha particle?
    Do you set it up like this?
    23.1×10^6(1.602×10^-13)(6.02×10^23)/10^3
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    #4

    Mar 28, 2008, 02:03 PM
    Quote Originally Posted by chemdiaster
    Do you have to do anything with the alpha particle?
    Do you set it up like this?
    23.1×10^6(1.602×10^-13)(6.02×10^23)/10^3
    Nope, nothing special, but some of your powers here are a bit confused.

    1.602×10^-13 is the number of Joules in an MeV, so take that into account.
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    #5

    Mar 28, 2008, 02:15 PM
    so should it be 1.602×10^-19?
    With an answer of 2.23×10^3 kJ/mole
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    #6

    Mar 28, 2008, 02:31 PM
    Are you sure? Just looking at the powers it looks to be around 10^7
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    #7

    Mar 28, 2008, 02:38 PM
    this is how I set it up~
    23.1MeV/ particle=
    (23.1×10^6 eV/particle)(1.602×10^-19 J/ 1eV)(kJ/1×10^3 J)( 6.02×10^23 particles/1 mole)
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    #8

    Mar 28, 2008, 02:57 PM
    I get 2.23x10^9 kJ/mol from that calculation.
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    #9

    Mar 28, 2008, 03:06 PM
    After recalcutlating it I got that answer. Do you know anything about radioactive and stable nuclides?
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