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ashliss07
May 9, 2007, 12:25 PM
Doe anyone know some of these answers? Please help!! :confused:

x + y = 10
x - y = 4



4x - 3y = -2
-2x + 3y = 4


3x - 4y = -2
4x - 3y = -5



x + 4y = -5
3x + y = -4


2x - y = 10
x + 2y = -5

ebaines
May 9, 2007, 12:48 PM
Ashliss07:

We won't do your homework for you, but here is a hint:

Each problem you've listed is a pair of statements with two unkowns (x and y). Take one of the statements and rephrase it so that either the x or the y is by itself on one side of the equation. You can then substitute that value into the other statement to determine one of the values. For example: the first problem includes the equation: x-y = 4. You can add y to both sides of the equal sign to get: x = 4+y. Do you see that? Then substitute this value for x into the first equation, so that x+y = 10 becomes (4+y) + y = 10. Now you can solve for y. Get it?

Capuchin
May 9, 2007, 01:02 PM
ebainesm the topic says to solve using elimination, not substitution.

Ashliss07, if you look at your first pair of equations, you see that you have +y in one and -y in the other. If you add the equations together, you get 2x = 14 because the y terms disappear, this gives you a value for x, which you can use to solve for y.

In the later questions, you might have to multiply up one of your equations in order to get a term that will disappear.

Please ask if you need further help.

deez5112
Jun 26, 2010, 01:57 PM
x+y=8,000
x+y=600

deez5112
Jun 26, 2010, 01:57 PM
x+y=8,000
x+y=600

Unknown008
Jun 27, 2010, 05:08 AM
The problem you posted here, deez5112 doesn't have any solutions. If, however, you meant:

x + y = 8 000
x - y = 600

Then, that's something different. Add the two equations:


x + y = 8000
x - y = 600
2x + 0 = 8600

Now that you have only one variable, you can solve the rest. :)