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View Full Version : The Quadratic Formula and Discriminant?


rocktober31
Apr 24, 2007, 03:01 PM
:confused: :( *screams in horror*

I seriously need help with this problem!!

3x(squared) +1=2x :eek: this is the formula! -b + - (square root of) b(squared) - 4 ac
all divided by 2a

please help!! :confused:

this is 9th grade algebra!!

Capuchin
Apr 24, 2007, 11:27 PM
You need to put it into the form ax^2 + bx + c = 0

then you can put a b and c into the equation.

Have a go first, we will help you further if you are still stuck.

rocktober31
Apr 26, 2007, 01:37 PM
:confused: :( *screams in horror*

I seriously need help with this problem!!!

3x(squared) +1=2x :eek: this is the formula! -b + - (square root of) b(squared) - 4 ac
all divided by 2a

please help!!!!!!!!:confused:

this is 9th grade algebra!!!
Okay I did that. Thanks. Before I can rate that answer, I have to spread my rep. around.

I give it a 10 though!!

Capuchin
Apr 26, 2007, 02:03 PM
Glad I could help.

Jessuka1623
May 3, 2007, 06:56 AM
:confused: :( *screams in horror*

I seriously need help with this problem!!!

3x(squared) +1=2x :eek: this is the formula! -b + - (square root of) b(squared) - 4 ac
all divided by 2a

please help!!!!!!!!:confused:

this is 9th grade algebra!!!
subtract 2x from both sides so you get: (^2=squared)

3x^2-2x+1=0

the work the problem from there...

2 +- sqr. root of -2^2-4*1*3
2*2