Will it be right to say √-36=±6i? If no then please tell why.

It is correct:

(6i)^2 = 6^2i^2 = 36 (-1) = -36

(-6i)^2 = (-6)^2 i^2 = 36 (-1) = -36

Thanks!

√-36= 6i

since -36 can be written as -1*6*6 or -1*6^2
therefoe \sqrt(-36)=\sqrt(-1*6^2)
=6\sqrt(-1)
=6i {since \sqrt(-1)=i}

√-36= 6i

since -36 can be written as -1*6*6 or -1*6^2
therefoe \sqrt(-36)=\sqrt(-1*6^2)
=6\sqrt(-1)
=6i {since \sqrt(-1)=i}

You are commenting on a post that is almost a year old. The correct answer is \sqrt {-36} = \pm 6i as shown in earlier posts. Rememeber that -36 can also be written as -1 \ \times \ (-6)^2.