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View Full Version : Sec^-1 (- sqrt2)


Jakeman95
Oct 3, 2011, 09:34 AM
I need to find the exact value. I'm pretty lost.

jcaron2
Oct 3, 2011, 08:20 PM
I'm assuming this means arcsec(-sqrt(2))?

So this is essentially asking "What angle has a secant of -sqrt(2)?". If it has a secant of -sqrt(2), then (since secant = 1/cosine) it has a cosine of -1/sqrt(2), which is equal to -sqrt(2)/2.

So what angle has a cosine of -sqrt(2)/2? I'm guessing you know the answer.