View Full Version : Simplifying radical expressions
kellymae
Jan 29, 2011, 10:02 AM
Square root of 216v
Unknown008
Jan 29, 2011, 10:04 AM
Is that it?
\sqrt{216v}
And... you need to simplify that?
Okay, break up the 216 into its prime factors, can you post what you get?
kellymae
Jan 29, 2011, 10:18 AM
OK I factored it out and got 3 and 72 then I continued and got 6 square root of 2 and 3 as me answer is that right
kellymae
Jan 29, 2011, 10:25 AM
I got 6 and the square root of 2 and 3
Unknown008
Jan 30, 2011, 05:50 AM
Okay, you should get this:
\sqrt{216}v = \sqrt{36 \times 2 \times 3}v = 6\sqrt{6} v
When you can't find any square number, that's it and 6 radical 6 v is the answer.
Well done! :)