A numerator of a fraction is 2 less than its denominator. When both numerator and denominator are increased by 3 the fraction is increased by 3/20. Find the original fraction?

A numerator of a fraction is 2 less than its denominator. When both numerator and denominator are increased by 3 the fraction is increased by 3/20. Find the original fraction?

You are looking for a fraction. That means it is in the form \frac{a}{b}

You are told that a here is less than b by 2.
Also, you are told that if a and b are increased by 3, that means they each become (a+3) and (b+3) respectively, it is in fact increased by 3/20.

From the first part, you have a + 2 = b.

From the second part, you have

\frac{a+3}{b+3} = \frac{a}{b} + \frac{3}{20}

Can you solve the problem now?

Can u solve it more further please
'

Show first how you would do to solve that. It doesn't matter if it's wrong or not. The important thing is that you try.

Its answer is coming 8 and 5 but the real answer is 3/5 plzz solve it

The word 'show' implies that you give the steps that you followed. When you show these, we'll see where you are making the mistake and give the appropriate help.

4/9