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hslove142331
Feb 17, 2010, 08:34 PM
What is the rate law for the reaction? (Note: Choose as many answers as appropriate.)


The following data were obtained for the reaction of (CH3)3CBr with hydroxide ion at 55 oC.

(CH3)3CBr + OH- (CH3)3COH + Br-

Initial Concentration (mol L-1)
[(CH3)3CBr]

0.1
0.2
0.3
0.1
0.1

Initial Concentration (mol L-1)
[OH-]

0.1
0.1
0.1
0.2
0.3

Rate of Formation
of (CH3)3COH
(mol L-1 s-1)

0.001
0.002
0.003
0.001
0.001

What is the rate law for the reaction? (Note: Choose as many answers as appropriate.)
.
1.Rate = k[(CH3)3CBr]^0

2.Rate = k[(CH3)3CBr][OH-]^0

3.Rate = k[(CH3)3CBr]^0[OH-]

4.Rate = k[(CH3)3CBr][OH-]

5.Rate = k[(CH3)3CBr]

first time I choose 4. but it was incorrect and then I choose 2. it was incorrect either. I didn't put 4,2 together , I did separately
it says Choose as many answers as appropriate.

make me confusing , please help me

Unknown008
Feb 18, 2010, 09:06 AM
I think you have to say that they are 2 and 5, since [OH-]^0 = 1.