hslove142331
Feb 17, 2010, 08:34 PM
What is the rate law for the reaction? (Note: Choose as many answers as appropriate.)
The following data were obtained for the reaction of (CH3)3CBr with hydroxide ion at 55 oC.
(CH3)3CBr + OH- (CH3)3COH + Br-
Initial Concentration (mol L-1)
[(CH3)3CBr]
0.1
0.2
0.3
0.1
0.1
Initial Concentration (mol L-1)
[OH-]
0.1
0.1
0.1
0.2
0.3
Rate of Formation
of (CH3)3COH
(mol L-1 s-1)
0.001
0.002
0.003
0.001
0.001
What is the rate law for the reaction? (Note: Choose as many answers as appropriate.)
.
1.Rate = k[(CH3)3CBr]^0
2.Rate = k[(CH3)3CBr][OH-]^0
3.Rate = k[(CH3)3CBr]^0[OH-]
4.Rate = k[(CH3)3CBr][OH-]
5.Rate = k[(CH3)3CBr]
first time I choose 4. but it was incorrect and then I choose 2. it was incorrect either. I didn't put 4,2 together , I did separately
it says Choose as many answers as appropriate.
make me confusing , please help me
The following data were obtained for the reaction of (CH3)3CBr with hydroxide ion at 55 oC.
(CH3)3CBr + OH- (CH3)3COH + Br-
Initial Concentration (mol L-1)
[(CH3)3CBr]
0.1
0.2
0.3
0.1
0.1
Initial Concentration (mol L-1)
[OH-]
0.1
0.1
0.1
0.2
0.3
Rate of Formation
of (CH3)3COH
(mol L-1 s-1)
0.001
0.002
0.003
0.001
0.001
What is the rate law for the reaction? (Note: Choose as many answers as appropriate.)
.
1.Rate = k[(CH3)3CBr]^0
2.Rate = k[(CH3)3CBr][OH-]^0
3.Rate = k[(CH3)3CBr]^0[OH-]
4.Rate = k[(CH3)3CBr][OH-]
5.Rate = k[(CH3)3CBr]
first time I choose 4. but it was incorrect and then I choose 2. it was incorrect either. I didn't put 4,2 together , I did separately
it says Choose as many answers as appropriate.
make me confusing , please help me