kx - 3y + 7 = 0 is parallel to the line with gradient 5, what is the value for k?


Y=MX+C

KX-3y+7=0
3y=5X+7
Y=(5/3)X + 7

K=5/3

No, you didn't understand well the method to do it.

Yes, you need to put it in the form of Y = mX + C

kx - 3y + 7 = 0

Adding y on both sides;

kx + 7 = 3y

Rearrange;

3y = kx + 7

Divide both sides by 3;

y = \frac{k}{3} x + \frac73

Now, it's in the form Y = mX + C.

Since m is the gradient, and is 5, hence;

m = 5 = k/3

Can you solve it now?