f'(x)= x^2√2x^3+1

what's f(x)

I get the concept and did well on my test, but I just can't seem to figure out how to get the answer.

the answer is 1/9(2x^3=1)^3/2+C

Pleasw, please, use parentheses to make the equations clearer! I'm guessing that what you mean is:


f'(x) = x^2 \sqrt { 2x^3+1}


and

f(x) = \frac 1 9 (2x^3 +1)^{3/2} + C


Is that correct?

First steps first - do you see that the derivative of f(x) is indeed equal to f'(x) as written?