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Solve the equation
barons11
Jun 11, 2008, 12:07 PM
log(1000 x^2)=(log x)^2
ebaines
Jun 11, 2008, 12:31 PM
Like this:
log(1000 x^2) = [log(x)]^2 \\
log(1000) + 2 log(x) = [log(x)]^2 \\
(log(x))^2 - 2 log (x) - log(1000) = 0
Now use the quatratic equation to solve for log(x), and from that you can determine x.