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barons11
Jun 11, 2008, 12:07 PM
log(1000 x^2)=(log x)^2

ebaines
Jun 11, 2008, 12:31 PM
Like this:


log(1000 x^2) = [log(x)]^2 \\
log(1000) + 2 log(x) = [log(x)]^2 \\
(log(x))^2 - 2 log (x) - log(1000) = 0


Now use the quatratic equation to solve for log(x), and from that you can determine x.