I missed a few pre-calc classes and I don't understand how to solve for theta. How do I do this problem??
heeeeelp please



2sin^2(theta)=3(1-cos(theta))^2

2sin^{2}{\theta}=3(1-cos{\theta})^{2}

Use sin^{2}{\theta}=1-cos^{2}{\theta}

2-2cos^{2}{\theta}=3-6cos{\theta}+3cos^{2}{\theta}

5cos^{2}{\theta}-6cos{\theta}+1=0

Now, you can let u=cos{\theta}

5u^{2}-6u+1=0

Now, solve the quadratic and resub.