gmh69
Oct 2, 2007, 01:38 PM
Given x^2-y^2, find dy/dx by implicit differentiation
rebel-2
Oct 3, 2007, 04:57 AM
Given x^2-y^2, find dy/dx by implicit differentiation
Hello there do you mean y=x²-y²
my knowledge is limited but i think this is how you do it, lmao.:D
y=x²-y²
dy/dx=2x-2y
and that's all for differentiation, i think... use nx^n-1.
Mabey someone else here will explain this to us
galactus
Oct 3, 2007, 02:17 PM
Is that x^{2}-y^{2}=0?
Is it y=x^{2}-y^{2}
y=x^{2}-y^{2}
y-x^{2}+y^{2}=0
\frac{dy}{dx}-2x+2y\frac{dy}{dx}=0
Solve for dy/dx:
\fbox{\frac{dy}{dx}=\frac{2x}{1+2y}}