Given x^2-y^2, find dy/dx by implicit differentiation

Given x^2-y^2, find dy/dx by implicit differentiation

Hello there do you mean y=x²-y²
my knowledge is limited but i think this is how you do it, lmao.:D

y=x²-y²
dy/dx=2x-2y

and that's all for differentiation, i think... use nx^n-1.

Mabey someone else here will explain this to us

Is that x^{2}-y^{2}=0?

Is it y=x^{2}-y^{2}



y=x^{2}-y^{2}

y-x^{2}+y^{2}=0

\frac{dy}{dx}-2x+2y\frac{dy}{dx}=0


Solve for dy/dx:


\fbox{\frac{dy}{dx}=\frac{2x}{1+2y}}