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karly_brown1
Mar 19, 2018, 05:55 PM
Hello, I'm really struggling with this calculus homework. Please help!

According to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation, there were over 71 million wildlife watchers in the US. Of these wildlife watchers, the survey reports that 80% actively observed mammals. Suppose that one of the census workers repeated the survey with a simple random sample of only 500 wildlife watchers that same year.

Assuming that the original survey's 80% claim is correct, what is the approximate probability that between 79% and 81% of the 500 sampled wildlife watchers actively observed mammals in 2011?


a.) P(0.79< p ^ ​ <0.81)≈0.46


b.) P(0.79< p ^ ​ <0.81)≈0.54


c.) P(0.79< p ^ ​ <0.81)≈0.65

d.) P(0.79< p ^ ​ <0.81)≈0.42

smoothy
Mar 20, 2018, 04:22 AM
This is your homework, show us your work and what you think the answer is and why. Those are this sites rules.