A cannon sends a projectile towards a target
A distance 1590 m away. The initial velocity
Makes an angle 40◦ with the horizontal. The
Target is hit. How high is the highest point of the trajec-
Tory?

Here's the method to use:

1. Set up the equation for the horizontal compomnent of motion:


x = v_0 cos(40) t = 1590m


where v_0 is the initial veocity of the projectile out of the cannon and t is the time it taks to reach the target.

2. The equation for the vertical component of motion is:


y = v_0 sin(40) t -1/2gt^2 = 0


3. Now you have two equations in two unknowns, and you need to solve for t. Then determine the value for y at time t/2.

Post back with what you get for an answer.