A cat chases a mouse across a 1.3 m high
Table. The mouse steps out of the way, and
The cat slides off the table and strikes the floor
1.0 m from the edge of the table.
The acceleration of gravity is 9.81 m/s2 .
What was the cat’s speed when it slid off
The table?
Answer in units of m/s.

First of all consider what happens vertically.

Initial vertical speed of cat = 0m/s
g = 9.81m/s2
distance the cat fell = 1.3 m

use the formula d = ut +1/2 gt^2 you have all values except t so solve for t.

1.3 = 0 x t + 1/2 x 9.81 t^2
1.3=4.905t^2
t^2=1.3/4.905
t=square root (1.3/4.905)
t= 0.515 seconds

now consider what is happening horizontally
the cat moved a distance of 1.0m in a time of 0.515 s

so v = d/t
v= 1/0.515
v = 1.9 m/s