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RhodesKL
Oct 12, 2006, 06:44 PM
Is there any easy way to find the derivative of an exponential or logarithmic function? Or can anyone explain it simply?

LucyMcgoo
Oct 12, 2006, 10:21 PM
I say the ol' trusty scientific calculator!

JOHNSMITH55
Oct 19, 2006, 02:39 AM
loge(f(x))
the derivative is
f'(x) divided by f(x)

e^kx
the derivative is
ke^kx
(the k is a constant and is the derivative of the part that the "e" is powered to


Hope this helps:)

s_cianci
Nov 1, 2006, 09:06 PM
The derivative of an exponential function is proportional to itself and is the only type of function with that property. That said, [d/dx] a^u = (a^u)(Ln a)(du/dx), the proportionality constant being Ln a. If a is the natural base, which is e (Euhler's Number), then Ln e = 1 and [d/dx] e^u = (e^u)(du/dx). The derivative of a logarithmic function is its reciprocal, times the derivative of its argument, divided by the natural logarithm of the base. That is, [d/dx] log a u = (1/u)(du/dx)(1/(Ln a))

ahmedgawi
Mar 14, 2014, 04:51 AM
y=C.e^ax