How many grams are in 5.66 mol of CaCO3?

The formula is

Number of moles = [Mass of sample (g)] / [Relative molecular mass (g/mol)]

The RMM of calcium carbonate is 100 g/mol.

The mass is therefore 100 (g/mol) * 5.66 (mol) = 566g.

You should know the mass of CaCo3 and that will be 217 g.
So when you convert it it would be:


In 1 mole=217g
And we have 5.66 mol so far

You have to do is 217 times 5.66 you get=1228.22
Since we started by three significant figures your answer would be in whole number and that would be 1228 mol.

You should know the mass of CaCo3 and that will be 217 g.
So when you convert it it would be:


In 1 mole=217g
And we have 5.66 mol so far

You have to do is 217 times 5.66 you get=1228.22
Since we started by three significant figures your answer would be in whole number and that would be 1228 mol.

This is totally wrong.

1 mol of CaCO_3 (NOT CaCo3) has a mass of 100 g, NOT 217 g

5.66 mol of CaCO3 will have a mass of 566 g

NOT 1228.22 mol, which isn't even a mass. This is just plain wrong, you start with 5.66 mol and end up with 1228.22 mol?

Plus this thread was revived. THREAD CLOSED