Question: Quadratics Equation View Single Post
 rpray2007 Posts: 320, Reputation: 110 Full Member #2 Apr 10, 2012, 04:59 PM
Would be glad to help and if you tell us where you are stuck, we're more than happy to help.

$x{\small_1}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$
In your case, $k$ is the same as $b$ and $a$ is $-1$