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Uber Member
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May 11, 2007, 08:28 AM
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Just going to post the math.
You start with 6 ounces in each glass. You move one ounce of red into the white.
The white glass now has 6 ounces white and 1 ounce red. The red glass has 5 ounces red.
Then you move one ounce back. This one ounce contains 1/7 ounce red and 6/7 ounce white. (the proportions that are in the white glass)
So, subtracting this from the white glass we have 6/7 ounce red and 5 1/7 ounce white.
Adding to the red glass we have 5 1/7 ounce red and 6/7 ounce white.
They are both contaminated by the same amount! It's unintuitive until you actually do the math :)
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Junior Member
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Aug 16, 2007, 11:15 PM
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Um I would say that the one that was originally all red was contaminated more.
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Uber Member
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Aug 16, 2007, 11:29 PM
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(psst check the solution above your post) :)
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Junior Member
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Aug 17, 2007, 11:57 AM
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OK capuchin. The way I dd it it cam eout that the red was more contaminated but whatever.
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Uber Member
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Aug 17, 2007, 12:15 PM
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Can you see a flaw in my working? I'd like you to point out where I am wrong.
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Full Member
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Aug 17, 2007, 12:17 PM
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Ah, Capuchin. You are mathematically correct. But given that red wine is far superior to white, wouldn't the white glass be 5 1/7 ounces contaminated with only 6/7 ounces of good?:p
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Ultra Member
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Aug 17, 2007, 12:20 PM
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Isn't this question from forever ago? I remember this from when I first started I think. ;)
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Junior Member
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Aug 17, 2007, 03:00 PM
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No need to get mad capuchin. In my weird mind it cam eout the red is more ontaminated. Bbut you are probably corredt. I don't wish to work it out write now. I got it wrong. Oh well.
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Junior Member
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Aug 27, 2007, 05:39 PM
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Contami- wha? HEY! The glasses are empty *BURP* whooo! Uh, they are both comtomintated he he he he *falls over*
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