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    INeedHelp505's Avatar
    INeedHelp505 Posts: 3, Reputation: 1
    New Member
     
    #1

    Apr 3, 2005, 01:50 PM
    A prize if you can answer this...
    This is for all you calculus people...

    a) Solve this both by partial fractions and integration by parts
    b) Show that the answers are equivalent



    If you can get this, I'll send you this gift
    http://www.thewholesaledetective.com/?hop=psprpspr
    INeedHelp505's Avatar
    INeedHelp505 Posts: 3, Reputation: 1
    New Member
     
    #2

    Apr 4, 2005, 05:11 PM
    The Prize
    Ok now, instead of the wholesale list, the new prize is the ebook David Blane's Magic Secrets Revealed.
    psi42's Avatar
    psi42 Posts: 599, Reputation: 13
    Senior Member
     
    #3

    Apr 5, 2005, 10:07 PM
    INeedHelp505,

    You do realize no one is going to answer your question because you offered as a "reward" something most people would pay you _not_ to give them...
    Dr_Calculus's Avatar
    Dr_Calculus Posts: 35, Reputation: 1
    Junior Member
     
    #4

    Apr 9, 2005, 03:56 PM
    Lol
    Yeah, that's true... I don't even know how to integrate by partial fractions yet... I'm still in calc AB. I do know how to integrate by parts though, I got bored in class. Nonetheless. I'm just too lazy to answer that question.
    MathMaven53's Avatar
    MathMaven53 Posts: 20, Reputation: 2
    New Member
     
    #5

    Jun 29, 2005, 02:19 PM
    I Need Help
    Some times partial fractions can be easily done.

    Lets get the function x^2 in terms of x+2

    x^2 = [x+2-2]^2

    = (x+2)^2 -4(x+2)+ 4

    Then x^2 /(x+2)^3 = 1/(x+2) -4(x+2)^2 +4/(x+2)^3
    by division of each term by denominator on left.

    Each of these terms can be integrated.

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