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    bluedicius's Avatar
    bluedicius Posts: 20, Reputation: 1
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    #1

    Mar 13, 2005, 08:06 AM
    exponential decay
    The radioactive decay formula is A = A0(1/2)^t/n, where A is the current amoutn of the radioactive sample, A0 is the original amount, t is the elapsed time and n is the length of the half life.

    The half life of Sodium-24 is 14.9h. A researcher begins with 100mg of sodium-24. What is the exponential decay equation for this sample of sodium-24?
    How much of the sample will be remaining in 48hours?
    How long will it take until the sample decays to only 1mg of sodium-24?
    reinsuranc's Avatar
    reinsuranc Posts: 92, Reputation: 6
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    #2

    Mar 14, 2005, 07:17 AM
    Exponential decay
    A = (Ao) * (.5 ^ (t/n))
    A = (100) * (.5 ^ (t/14.9))

    1. (100) * (.5 ^ (48/14.9)) = 10.72


    2. 1 = (100) * (.5 ^ (t/14.9))
    LN(1) = LN[ (100) * (.5 ^ (t/14.9)) ]
    LN(1) = LN(100) + LN[ (.5 ^ (t/14.9)) ]
    LN(1) = LN(100) + (t/14.9) * LN(.5)
    14.9 * [ LN(1) - LN(100) ] / LN(.5) = t
    14.9 * [ 0 - 4.60517 ] / -.69315 = t
    t = 98.99

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