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    xsw21232's Avatar
    xsw21232 Posts: 1, Reputation: 1
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    #1

    Mar 12, 2015, 06:06 AM
    I need help in solving permutation sum
    In how many ways can a person can courier/parcel to his 5 friends if he has four courier options.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Mar 12, 2015, 01:10 PM
    For friend A there are four possible ways to send a parcel, call then A1, A2, A3, and A4. For friend B there are also four ways - B1, B2, B3,and B4 - so between both friends A and B there are 4x4 = 16 different possible combinations. It can help to write these out so that see how it works:

    A1&B1, A1&B2, A1&B3, A1&B4
    A2&B1, A2&B2, A2&B3, A2&B4
    A3&B1, A3&B2, A3&B3, A3&B4
    A4&B1, A1&B2, A4&B3, A4&B4

    So now how would this extend to include a third friend? And how about a fourth, and finally a fifth friend?
    fgsfgsfd's Avatar
    fgsfgsfd Posts: 1, Reputation: 1
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    #3

    Mar 12, 2015, 11:57 PM
    Could you differentiate the two sums below
    1.In how many ways can a person can courier/parcel to his 5 friends if he has four courier options.
    2. In how many ways can 4 gifts be distributed to 6 children if each child get any number of gifts

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